One equation to calculate a warmth change is $q = c_p cdot m cdotDelta T$. I know that $Delta T$ can be in either levels Celsius ($^circmathrmC$) or kelvin ($mathrmK$). However before, one point that confuses me is just how the devices cancel if $Delta T$ is in degrees Celsius, because $c_p$ has actually systems of $mathrmJ g^-1 K^-1$. How does this work?


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Elaborating Ron’s answer via a concrete example, we begin by looking at the Celsius scale

$$ T_ extC1 = 25 mathrm^circ C ,~ T_ extC2 = 100 mathrm^circ C$$

Therefore, we obtain

$$ Delta T_ extC = T_ extC2 - T_ extC1 = 100 mathrm^circ C - 25 mathrm^circ C = 75 mathrm^circ C $$

In a comparable fashion, utilizing the Kelvin scale

$$ T_ extK1 = 298.15 mathrm K = (273.15 + 25) mathrmK,~ T_ extK2 = 373.15 = (273.15 + 100) mathrmK$$

Therefore, we obtain

$$ Delta T_ extK = T_ extK2 - T_ extK1 = (273.15 + 100) mathrmK - (273.15 + 25) mathrmK = 75 mathrmK $$

As you can check out, the consistent offset of 273.15 in between the Celsius range and also the Kelvin range cancels, and the distinction is precisely the very same. The units reprimary, yet the numerical value of the difference is the exact same.

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edited Mar 31 "15 at 19:20
user7951
answered May 28 "14 at 9:44
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Kjetil SonerudKjetil Sonerud
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The temperature in kelvin is equal to the temperature in degrees Celsius plus 273.

So, $Delta T$ will be the very same whether the temperature was reported in $mathrmK$ or $^circmathrmC$. As an example if $T_mathrminitial = 0 ^circmathrmC (273 mathrmK)$ and $T_mathrmfinal = 100 ^circmathrmC (373 mathrmK)$, $Delta T$ is 100 degrees no issue whether you used $^circmathrmC$ or $mathrmK$ in your computation.


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edited Oct 10 "16 at 7:04
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answered Apr 11 "14 at 21:54
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ronron
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If your specific heat has actually units of degrees Celsius in it then usage the temperatures in levels Celsius to discover $Delta T$. Although, the difference would certainly be precisely the very same as if you provided kelvin as 1 level distinction is the very same on both scales. Nonetheless, I would discourage making use of degrees Celsius as the SI unit is kelvin and also is the one that"s normally used.


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edited Oct 10 "16 at 7:08
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answered Oct 9 "16 at 22:36
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VladVlad
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$egingroup$ Note that both the kelvin and the degree Celsius are SI devices. $endgroup$
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