A Rubik cube normally have 6 sides. Take 3×3 rubik cube for example, each side has actually 9 little bit squares (1×1), 4 medium squares (2×2) and 1 significant square (3×3). As such, tright here are 6 x (9 + 4 + 1) = 84 squares on a 3×3 rubik cube.
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How around counting the rectangles? It is a little bit difficult to count. Let’s compose a duty to count it. The algorithm is to bruteforce a pair of points (from top left edge to the right bottom). Then we compute the two sides of the rectangle to see if it is a square.
|function countSquaresAndRectangles(N) let squares = 0; let rectangles = 0; for (let a = 0; a N; a ++) for (let b = 0; b N; b ++) for (let c = a + 1; c N; c ++) for (let d = b + 1; d N; d ++) if (d - b === c - a) squares ++; else rectangles ++; return <6 * squares, 6 * rectangles>;let ans = countSquaresAndRectangles(3);console.log("There are " + ans<0> + " squares, and " + ans<1> + " rectangles.");|
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Tright here are 840 squares, and also 3864 rectangles for a 7×7 rubik cube.
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