We are doing a testimonial of what the previous semester talked about, yet I took the initially component of chemisattempt in summer 2007. Needmuch less to say I am rusty and really don't understand where to begin through this.Calculate the total number of ions present in 75.2g SrF2.If I remember correctly the F2 is the ionic part. The molar mass of F2 is 38g/mol. Wright here must I go now?


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UGFull MemberPosts: 822Mole Snacks: +134/-15Gender:
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The entire compound SrF2 is an ionic compound, it consists of cations (positive ions) and also anions (negative ions) choose all ionic compounds. The cation below is Sr2+ and the anion is F-. Tbelow are 2 F- ions for eexceptionally one Sr2+ ion so that the as a whole charge is neutral. Now to calculate the variety of ions current. You must discover the molar mass of the whole compound. Then, utilizing the mass given and also molar mass to find the variety of moles of SrF2 present. Once you have actually this, can you calculate the complete variety of ions present in the compound (provided the information I provided at the beginning)? Think if you had one mole of SrF2, how many kind of ions are present altogether?
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hokychikRegular MemberPosts: 9Mole Snacks: +0/-0Gender:
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Ok, so the molar mass of the molecule is 125.6g/mol. So 75.2g SrF2/125.6g SrF2 is .599 moles SrF2, correct? I don't really understand exactly how to acquire the number of ions though. From what you are saying (if I am knowledge right), tright here are 3 ions current. Do I should obtain the number moles of each ion existing (from the calculated complete number of moles for the molecule)?
Yes correct tright here are three ions present, so all you must execute is multiply 0.599 by three and also you will have actually your last answer
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It still states it is wrong though. I did .599 mol * 3 ions= 1.797 ions and it wants it in the develop of (#)*10^(#) so i put 1.80*10^0 (to store with the substantial figures). Did I need to use Avogadro's number in there somewhere? It is among hints offered as soon as I acquired it wrong.


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Ooo
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, of course, the total number of ions, not number of moles, silly me. Yes, then you have to multiply the variety of moles of ions by Avagadro's number