iped out. The hydrometer is first dropped in water, and also the water level is marked. The hydrometer is then dropped right into the other liquid, and also it is observed that the mark for water has actually risen 0.3 cm over the liquid–air interconfront (Fig. P11–31). If the elevation of the original water note is 12.3 cm, determine the density of the liquid.


You are watching: The density of a liquid is to be determined by an old


muzic-ivan.info:

The thickness of the unrecognized liquid is 1.025 kg/m³ (considering the density of the water as 1.000 kg/m³)

Explanation:

The hydrometer functions by the Archimedes principle. The cylinder floats in the liquid bereason the hydrostatic thrust is equal to the weight force. This means:

*

If we measure 2 fluids, the weight of the hydrometer is the very same, so:

*

If the original watermark elevation is 12.3cm (H₁) and also the note for water has risen 0.3 cm above the unwell-known liquid–air interface, the elevation of the unwell-known liquid note is 12cm (H₂). Therefore:

*


Sfinish
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Exsimple at least three ways that Engineers check out possible remedies in their projects
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muzic-ivan.info:

AFQ - Action Function Concern table

Know/Need to understand table

Weighted decision matrix

Explanation:

AFQ permits to view what materials, or just how something will be created by asking ourselves questions

Know/NTK is for doing research

Decision matrix is have to figure out what is the best concept and what you will be going via through in the last procedures of a job.


7 0
3 months ago

Nitrogen (N2) at 1 bar, 300 K enters a compressor operating at steady state and is compressed adiabatically to an leave state of
GrogVix <38>

muzic-ivan.info:

a) 358.8 KJ/kg

b) 0.0977 KJ/K- kg

c) 83.28%

Explanation:

N2 at 300 k. ( usage the properties of N2 at 300 k (T1) )

Cp = 1.04 KJ/kg-k , Cv = 0.743 KJ/Kgk , R = 0.1297 KJ/kgk , y = 1.4 ,

Given data:

T2 = 645 k

P1 = 1 bar , P2 = 10.5 bar

a)Determine the work-related input in KJ/Kg of N2 flowing

Winput = h2 - h1 = Cp( T2 - T1 ) = 1.04 ( 645 - 300 ) = 358.8 KJ/kg

b) Determine the price of entropy in KJ/K- kg of N2 flowing

Rate of entropy ( Δs ) = Cp*InT2/T1 - R*In P2/P1

= 1.04 * In (645/300) - 0.1297 * In ( 10.5 / 1 )

= 0.0977 KJ/K- kg

c) Determine isentropic compressor effectiveness

Isentropic compressor efficiency = 83.28%

calculated utilizing the relation below

( h"2 - h1 ) / ( h2 - h1 ) = ( T"2 - T1 ) / ( T2 - T1 )

where T"2 = 587.314


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Please assist !!!!!! I will give brilliant muzic-ivan.info to the right solution.​
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muzic-ivan.info:

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Explanation:

have actually a nice day


6 0
4 months ago

1. A generator in a heavy steam power plant operates isentropically via an inlet press (P3) of 3.5 MPa and inlet temperature (T3) of
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muzic-ivan.info:

See attached image.

Explanation:

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4 0
6 months ago
A lake is fed by a polluted stream and also a sewage outautumn. The stream and sewer wastes have a degeneration price coefficient (k) of 0.5/d
joja <24>

Equipment :

Given :

k = 0.5 per day

*

*

Volume, V

*

Now, input price = output rate + KCV ------------- (1)

Input price

*

*

*

The output price

*

= ( 40 + 0.5 ) x C x 1000

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Decay price = KCV

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= 1.16 C mg/s

Substituting all worths in (1)

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8 months ago
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