The worth of the cube root of 27 is 3. It is the genuine solution of the equation x3 = 27. The cube root of 27 is expressed as ∛27 in radical create and as (27)⅓ or (27)0.33 in the exponent develop. As the cube root of 27 is a entirety number, 27 is a perfect cube.

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Cube root of 27: 3Cube root of 27 in exponential form: (27)⅓Cube root of 27 in radical form: ∛27

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1.What is the Cube Root of 27?
2.How to Calculate the Cube Root of 27?
3.Is the Cube Root of 27 Irrational?
4.FAQs on Cube Root of 27

The cube root of 27 is the number which when multiplied by itself 3 times provides the product as 27. Because 27 have the right to be expressed as 3 × 3 × 3. Because of this, the cube root of 27 = ∛(3 × 3 × 3) = 3.


Cube Root of 27 by Prime Factorization

Prime factorization of 27 is 3 × 3 × 3Simplifying the above expression: 33

Thus, the cube root of 27 by prime factorization is (3 × 3 × 3)1/3 = 3.


No, because ∛27 = ∛(3 × 3 × 3) have the right to be expressed in the develop of p/q i.e. 3/1. Therefore, the value of the cube root of 27 is an integer (rational).

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Example 1: What is the value of ∛27 + ∛(-27)?

Solution:

The cube root of -27 is equal to the negative of the cube root of 27.i.e. ∛-27 = -∛27Therefore, ∛27 + ∛(-27) = ∛27 - ∛27 = 0


 

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FAQs on Cube Root of 27

What is the Value of the Cube Root of 27?

We can expush 27 as 3 × 3 × 3 i.e. ∛27 = ∛(3 × 3 × 3) = 3. As such, the worth of the cube root of 27 is 3.

If the Cube Root of 27 is 3, Find the Value of ∛0.027.

Let us represent ∛0.027 in p/q create i.e. ∛(27/1000) = 3/10 = 0.3. Hence, the value of ∛0.027 = 0.3.

Why is the worth of the Cube Root of 27 Rational?

The value of the cube root of 27 deserve to be expressed in the form of p/q i.e. = 3/1, wbelow q ≠ 0. Thus, the ∛27 is rational.

Is 27 a Perfect Cube?

The number 27 on prime factorization gives 3 × 3 × 3. On combining the prime factors in groups of 3 provides 3. So, the cube root of 27 = ∛(3 × 3 × 3) = 3 (perfect cube).

What is the Value of 2 Plus 8 Cube Root 27?

The worth of ∛27 is 3. So, 2 + 8 × ∛27 = 2 + 8 × 3 = 26. Hence, the worth of 2 plus 8 cube root 27 is 26.

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What is the Cube of the Cube Root of 27?

The cube of the cube root of 27 is the number 27 itself i.e. (∛27)3 = (271/3)3 = 27.